<?xml version="1.0" encoding="UTF-8" ?>
  <resource>
  <id>9751</id>
  <path>/www/nrich/html/content/id/9751/</path>
  <resourceTypeID>1</resourceTypeID>
  <last_published>2013-01-02T17:09:49</last_published>
  <indexXML>&lt;?xml version=&quot;1.0&quot; encoding=&quot;UTF-8&quot;?&gt;
&lt;mdoxml version=&quot;1.0&quot;&gt;&lt;mdo:image src=&quot;squares%20in%20circle.png&quot; style=&quot;float: right;&quot;&gt;&lt;/mdo:image&gt;&lt;br&gt;&lt;/br&gt;
&lt;br&gt;&lt;/br&gt;
&lt;br&gt;&lt;/br&gt;
The diagram shows a pattern of eight equal shaded squares inside a circle of area $\pi$ square units.&lt;br&gt;&lt;/br&gt;
&lt;br&gt;&lt;/br&gt;
&lt;br&gt;&lt;/br&gt;
What is the area (in square units) of the shaded region?&lt;br&gt;&lt;/br&gt;&lt;/mdoxml&gt;</indexXML>
  <solutionXML>&lt;?xml version=&quot;1.0&quot; encoding=&quot;UTF-8&quot;?&gt;
&lt;mdoxml version=&quot;1.0&quot;&gt;&lt;mdo:image src=&quot;squares%20in%20circle2.png&quot; style=&quot;float: right;&quot;&gt;&lt;/mdo:image&gt; Let the centre of the circle be $O$ and let $A$ and $B$ be corners of one of the shaded squares, as shown.&lt;br&gt;&lt;/br&gt;
&lt;br&gt;&lt;/br&gt;
As the circle has area $\pi$ square units, its radius is $1$ unit. So $OB$ is $1$ unit long.&lt;br&gt;&lt;/br&gt;
&lt;br&gt;&lt;/br&gt;
Let the length of the side of each of the shaded squares be $x$ units.&lt;br&gt;&lt;/br&gt;
By Pythagoras&amp;#39;s Theorem, $OB^2 = OA^2 + AB^2$, that is $1^2 = (2x)^2 + x^2$.&lt;br&gt;&lt;/br&gt;
So $5x^2=1$. Now the total shaded area is $8x^2 = 8 \times \frac{1}{5} = 1 \frac{3}{5}$ square units.&lt;/mdoxml&gt;</solutionXML>
  <noteXML/>
  <clueXML/>
  <canonXML/>
  <end_user_role>2</end_user_role>
  <difficulty>3</difficulty>
  <keystage1>0</keystage1>
  <keystage2>0</keystage2>
  <keystage3>1</keystage3>
  <keystage4>0</keystage4>
  <keystage4plus>0</keystage4plus>
  <title>Weekly Problem 5 - 2013</title>
  <description>Weekly Problem 5 - 2013</description>
  <spec_group>ajk44
    <specifier>Alison's dev tag</specifier>
  </spec_group>
</resource>