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  <resource>
  <id>740</id>
  <path>/www/nrich/html/content/00/11/six3/</path>
  <resourceTypeID>1</resourceTypeID>
  <last_published>2011-02-01T00:00:01</last_published>
  <indexXML>&lt;?xml version=&quot;1.0&quot; encoding=&quot;UTF-8&quot;?&gt;
&lt;mdoxml version=&quot;1.0&quot;&gt;&lt;br&gt;&lt;/br&gt;

&lt;p&gt;Some 4 digit numbers can be written as the product of a 3 digit
number and a 2 digit number using the digits $1$ to $9$ each once
and only once.&lt;/p&gt;
&lt;p&gt;The number $4396$ can be written as just such a product. Can you
find the factors?&lt;/p&gt;
&lt;p&gt;Maths is full of surprises! The number $5796$ can be written as
a product like this in two DIFFERENT ways, and so can the number
$5346$. Can you find these four funny factorisations?&lt;/p&gt;
&lt;p&gt;Here is another puzzle, again you must use the digits $1$ to $9$
once, but only once, to replace the stars and complete this
multiplication example.&lt;/p&gt;
 
&lt;table&gt;
&lt;tbody&gt;
&lt;tr align=&quot;center&quot;&gt;
&lt;td&gt;&lt;/td&gt;
&lt;td&gt;*&lt;/td&gt;
&lt;td&gt;*&lt;/td&gt;
&lt;td&gt;$9$&lt;/td&gt;
&lt;/tr&gt;
&lt;tr align=&quot;center&quot;&gt;
&lt;td&gt;&lt;/td&gt;
&lt;td&gt;&lt;/td&gt;
&lt;td&gt;$4$&lt;/td&gt;
&lt;td&gt;*&lt;/td&gt;
&lt;/tr&gt;
&lt;tr align=&quot;center&quot;&gt;
&lt;td&gt;---&lt;/td&gt;
&lt;td&gt;---&lt;/td&gt;
&lt;td&gt;---&lt;/td&gt;
&lt;td&gt;---&lt;/td&gt;
&lt;/tr&gt;
&lt;tr align=&quot;center&quot;&gt;
&lt;td&gt;*&lt;/td&gt;
&lt;td&gt;$6$&lt;/td&gt;
&lt;td&gt;*&lt;/td&gt;
&lt;td&gt;*&lt;/td&gt;
&lt;/tr&gt;
&lt;/tbody&gt;
&lt;/table&gt;
&lt;br&gt;&lt;/br&gt;

&lt;p&gt;This gives altogether six funny factorisations and there is one
more. You might like to write a computer program to find all seven
funny factorisations or you might come up with a different method.
Let us know.&lt;/p&gt;
&lt;br&gt;&lt;/br&gt;&lt;/mdoxml&gt;</indexXML>
  <solutionXML>&lt;?xml version=&quot;1.0&quot; encoding=&quot;UTF-8&quot;?&gt;
&lt;mdoxml version=&quot;1.0&quot;&gt;&lt;p&gt;Some 4 digit numbers can be written as the product of a 3 digit number and a 2 digit number using the digits 1 to 9 each once and only once.&lt;/p&gt;
&lt;p&gt;Well done Sally Nelson and Sarah Dunn, S2, Madras College, St Andrew&amp;#39;s for finding altogether six funny factorisations, but there is one more. It is now a Tough Nut to find the last one. You might like to write a computer program to find all seven funny factorisations or you might come up with a different method. Let us know.&lt;/p&gt;
&lt;p&gt;The number 4396 = 2 x 2 x 7 x 157 and there are not many possible combinations. By trial and error we get 4396 = 28 x 157.&lt;/p&gt;
&lt;p&gt;The number 5796 = 2 x 2 x 3 x 3 x 7 x 23.&lt;br&gt;&lt;/br&gt;
So 5796 = (2 x 3 x 7) x ( 2 x 3 x 23) or (2 x 2 x 3) x (3 x 7 x 23) amongst other possibilities which don&amp;#39;t turn out to be &amp;#39;funny&amp;#39;.&lt;br&gt;&lt;/br&gt;
In this way we find the two funny factorisations: 5796 = 42 x 138 and 5796 = 12 x 483.&lt;/p&gt;
&lt;p&gt;Similarly 5346 = 2 x 3 &lt;sup&gt;5&lt;/sup&gt; x 11 and the funny factorisations are:&lt;br&gt;&lt;/br&gt;
5346 = 27 x 198 and 5346 =18 x 297.&lt;/p&gt;
&lt;p&gt;Here you must use the digits 1 to 9 once, but only once, to replace the stars and complete this multiplication example.&lt;/p&gt;
&lt;table&gt;
&lt;tbody&gt;
&lt;tr align=&quot;center&quot;&gt;
&lt;td&gt; &lt;/td&gt;
&lt;td&gt;*&lt;/td&gt;
&lt;td&gt;*&lt;/td&gt;
&lt;td&gt;9&lt;/td&gt;
&lt;/tr&gt;
&lt;tr align=&quot;center&quot;&gt;
&lt;td&gt; &lt;/td&gt;
&lt;td&gt; &lt;/td&gt;
&lt;td&gt;4&lt;/td&gt;
&lt;td&gt;*&lt;/td&gt;
&lt;/tr&gt;
&lt;tr align=&quot;center&quot;&gt;
&lt;td&gt;---&lt;/td&gt;
&lt;td&gt;---&lt;/td&gt;
&lt;td&gt;---&lt;/td&gt;
&lt;td&gt;---&lt;/td&gt;
&lt;/tr&gt;
&lt;tr align=&quot;center&quot;&gt;
&lt;td&gt;*&lt;/td&gt;
&lt;td&gt;6&lt;/td&gt;
&lt;td&gt;*&lt;/td&gt;
&lt;td&gt;*&lt;/td&gt;
&lt;/tr&gt;
&lt;/tbody&gt;
&lt;/table&gt;
&lt;br&gt;&lt;/br&gt;
&lt;p&gt;Firstly I found out the possible solutions for the top row. It could not be a number above 250 or below 100 and it had to end in a 9. The number could not have a 4 or a 6 or another 9. The only possibilities were 129, 139, 159, 179, 189, 219 and 239. So I tried these numbers with every 2 digit number beginning with a 4 until I found the answer 159 x 48 = 7632.&lt;br&gt;&lt;/br&gt;
&lt;br&gt;&lt;/br&gt;
&lt;br&gt;&lt;/br&gt;
&lt;span class=&quot;editorial&quot;&gt;We received a Python program from Ryan for exhaustively finding solutions to the problem. You can download it &lt;a href=&quot;/content/00/11/six3/funnyfactorisation.py&quot;&gt;here&lt;/a&gt;&lt;/span&gt;&lt;/p&gt;&lt;/mdoxml&gt;</solutionXML>
  <noteXML/>
  <clueXML/>
  <canonXML/>
  <end_user_role>2</end_user_role>
  <difficulty>5</difficulty>
  <keystage1>0</keystage1>
  <keystage2>0</keystage2>
  <keystage3>1</keystage3>
  <keystage4>0</keystage4>
  <keystage4plus>0</keystage4plus>
  <title>Funny Factorisation</title>
  <description>Some 4 digit numbers can be written as the product of a 3 digit
number and a 2 digit number using the digits 1 to 9 each once and
only once. The number 4396 can be written as just such a product.
Can you find the factors?</description>
  <spec_group>Numbers and the Number System
    <specifier>Number - generally</specifier>
  </spec_group>
  <spec_group>Numbers and the Number System
    <specifier>Factors and multiples</specifier>
  </spec_group>
  <spec_group>Numbers and the Number System
    <specifier>Factors and multiples</specifier>
  </spec_group>
  <spec_group>Decision Mathematics and Combinatorics
    <specifier>Algorithms</specifier>
  </spec_group>
  <spec_group>Information and Communications Technology
    <specifier>smartphone</specifier>
  </spec_group>
</resource>