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  <resource>
  <id>6757</id>
  <path>/www/nrich/html/content/id/6757/</path>
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  <last_published>2011-02-01T00:00:01</last_published>
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&lt;mdoxml version=&quot;1.0&quot;&gt;&lt;br&gt;&lt;/br&gt;
&lt;p&gt;In Miss Quaffley&amp;#39;s class, the girls make up more than $45$% of the pupils, but less than $50$%. What is the smallest possible number of girls in her class?&lt;br&gt;&lt;/br&gt;
&lt;br&gt;&lt;/br&gt;
If you liked this problem, &lt;a href=&quot;http://nrich.maths.org/public/viewer.php?obj_id=1283&amp;amp;part=&quot;&gt;here is an NRICH task&lt;/a&gt; which challenges you to use similar mathematical ideas.&lt;/p&gt;
&lt;p&gt; &lt;/p&gt;&lt;/mdoxml&gt;</indexXML>
  <solutionXML>&lt;?xml version=&quot;1.0&quot; encoding=&quot;UTF-8&quot;?&gt;
&lt;mdoxml version=&quot;1.0&quot;&gt;&lt;br&gt;&lt;/br&gt;
Let $c$ denote the size of the class and $g$ denote the number of
girls. We want $0.45c&amp;lt; g&amp;lt; 0.5c\Leftrightarrow 0.45&amp;lt; 
\frac{g}{c}&amp;lt; 0.5$.&lt;br&gt;&lt;/br&gt;
&lt;br&gt;&lt;/br&gt;
If we try $g=1$ there is no such $c$, since if $c=1$ or $c=2$,
$\frac{g}{c}$ is too large, and if $c&amp;gt; 2$, $\frac{g}{c}$ is too
small.&lt;br&gt;&lt;/br&gt;
&lt;br&gt;&lt;/br&gt;
Similarly for $g=2$, $3$ or $4$. However for $g=5$ setting $c=11$
leads to $\frac{g}{c}=\frac{5}{11}=\frac{500}{11}$%
$=(\frac{440}{11}+\frac{60}{11})$%
$=(40+\frac{55}{11}+\frac{5}{11})$% $=45\frac{5}{11}$%.&lt;br&gt;&lt;/br&gt;&lt;/mdoxml&gt;</solutionXML>
  <noteXML/>
  <clueXML/>
  <canonXML/>
  <end_user_role>2</end_user_role>
  <difficulty>3</difficulty>
  <keystage1>0</keystage1>
  <keystage2>1</keystage2>
  <keystage3>1</keystage3>
  <keystage4>0</keystage4>
  <keystage4plus>0</keystage4plus>
  <title>Weekly Problem 3 - 2010</title>
  <description>

</description>
  <spec_group>Fractions, Decimals, Percentages, Ratio and Proportion
    <specifier>Percentages</specifier>
  </spec_group>
  <spec_group>Fractions, Decimals, Percentages, Ratio and Proportion
    <specifier>Calculating with percentages</specifier>
  </spec_group>
</resource>