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A pdf (f(x)) can never take a negative value as it is not possible
to have a negative probability. The curve which goes below the
x-axis is therefore not a pdf.<br></br>
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A pdf cannot have a 1 to many relationship, one outcome (x value)
cannot map to two different probabilites, hence the red curve
cannot represent a probability density function.<br></br>
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All remaning curves could represent a pdf.<br></br>
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The maximum value of the random variable of a circular arc pdf
passing through the origin will be equal to the diamater.We will
achieve the largest x value when we have a semi-circle passing
through the origin. The maximum value is therefore twice the radius
= 2.<br></br>
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