Kang of The Chinese High School of Singapore used algebra as follows:
Let Reza's present age be $x$
$x+3 = (x-3)^2$
$\Rightarrow x+3 = x^2 - 6x+9$
$\Rightarrow x^2-7x+6=0$
$\Rightarrow (x-1)(x-6)=0$
Therefore either $x = 1$ or $6$
Since Reza is at least $3$ years old, he must be $6$.
Renate and Amy of Hethersett High School suggested a very good method (see the table below). They noted that you can start with column (iii), then fill column (iv) with the squares of the numbers in (iii), then the age in column (i) is the mean of columns (iii) and (iv).
Similar tables came from Y8, Y9 and Y10 The Mount School York where they noticed that the ages are triangle numbers, as did Ying of Tao Nan School, Singapore, and also Mark ofKing Edward VI High School, Birmingham and Steven ofBedlington High School, Nothumberland.
| (i) | (ii) | (iii) | (iv) |
|---|---|---|---|
| Age | $k$ |
Age $k$ years ago
|
Age $k$ years ahead |
| $1$ | $0$ | $1$ | $1$ |
| $3$ | $1$ | $2$ | $4$ |
| $6$ | $3$ | $3$ | $9$ |
| $10$ | $6$ | $4$ | $16$ |
| $15$ | $10$ | $5$ | $25$ |
| $21$ | $15$ | $6$ | $36$ |
| $28$ | $21$ | $7$ | $49$ |
| $36$ | $28$ | $8$ | $64$ |
| $45$ | $36$ | $9$ | $81$ |
| $55$ | $45$ | $10$ | $100$ |