Investigating the dilution series

6164 /www/nrich/html/content/id/6164/ 1 2011-02-01T00:00:01 <?xml version="1.0" encoding="UTF-8"?> <mdoxml version="1.0"><ul id="stemLinks"> <li><a href="http://nrich.maths.org/6142">Warm-up</a></li> <li><a href="http://nrich.maths.org/6165">Try this next</a></li> <li><a href="http://nrich.maths.org/5511">Think higher</a></li> <li><a href="http://www.chemguide.co.uk/physical/equilibria/kc.html">Read: mathematics</a></li> <li><a href="http://en.wikipedia.org/wiki/Concentration">Read: science</a></li> <li><a href="http://plus.maths.org/content/how-leopard-got-its-spots">Explore further</a></li> </ul> <div> </div> Imagine that you create a four-step dilution series, where the amounts of culture passed from one stage to the next and the amount of medium added at each stage are multiples of 10 between 10ml and 100ml each time. In each case there are initially 100,000 cells/ml; the final concentration is given in the diagram as a rounded number.You can input your numbers into this interactive diagram (<a href="/content/id/6164/6164.swf" style="font-style: italic;">full screen mode</a> ): <mdo:flash height="180" id="/content/id/6164/6164.swf" width="550"><param name="allowfullscreen" value="true"></param><param name="allowfullscreen" value="true"></param> <param name="movie" value="/content/id/6164/6164.swf"></param> <param name="flashplayerversion" value="8"></param> </mdo:flash> Experiment with the dilution series to investigate these questions: <ol> <li>What are the lowest/highest possible final concentrations?</li> <li>How could you create final concentrations of 10, 100, 160, 20, 125 and 1875 cells/ml?</li> <li>At each stage of dilution, how many different dilution factors are possible?</li> <li>Could you, or how would you, create an exact 1/11 or 1/17 dilution?</li> <li>Could you, or how would you, create an exact 1/21 or 1/95 dilution?</li> <li>Explore impossible dilutions.</li> </ol> <div class="framework">NOTES AND BACKGROUND Dilution series are used in laboratories progressively to dilute a concentrated solution into a dilute solution. Diluting in the standard ratio 1:9 will create a solution of 10% of the concentration, otherwise called a 1/10 dilution. Successive 1/10 dilutions reduce the concentration by a factor of 10 each time, although other dilutions (as seen in this question) can be made by choosing other ratios.</div> </mdoxml> <?xml version="1.0" encoding="UTF-8"?> <mdoxml version="1.0"> 1) It is clear the highest concentration which is achievable is the original concentration of 100000 cells/ml, which results in transferring solution between subsequent beakers but without adding any additional water. <mdo:image height="119" width="417" src="D1.png" alt=""></mdo:image> The smallest concentration results from transferring the minimum amount of solution each time (10ml) but adding the maximum amount of water (100ml). This gives a minimum final concentration of 6 cells/ml. <mdo:image height="119" width="412" src="D2.png" alt=""></mdo:image> 2) It should be noted that for several of the required dilutions, there are more than one possible way to make them. However, only a single solution is provided below: a) To achieve a concentration of 10 cells/ml requires a dilution of 10,000 times. Since we have four opportunities to dilute the original solution, this logically requires a tenfold dilution each time. Thus, 10ml of solution should be transferred each time, and 90ml of water added to it. <mdo:image height="112" width="412" src="D3.png" alt=""></mdo:image> b) To give a concentration of 100 cells/ml, the same process should be repeated as in a) except that the final addition of water should not occur. Thus only three tenfold dilutions occur, and so the final concentration is 100 cells/ml as opposed to 10 cells/ml. <mdo:image height="107" width="400" src="D4.png" alt=""></mdo:image> c) To give a concentration of 160 cells/ml requires a 625 times dilution, which can be decomposed into a two 2.5x dilutions and two 10x dilutions. Thus, to give the required concentration involves taking 20ml of solution and adding 30ml of water, and then taking 10ml of solution and adding 90ml of water, before repeating both of these steps. <mdo:image height="112" width="405" src="D5.png" alt=""></mdo:image> d) To achieve a 20 cells/ml concentration is similar to that of the 10 cells/ml dilution, except that the final step is different. Rather than taking 10ml of solution and adding 90ml of water to give a tenfold dilution, 20ml of solution is taken and 80ml of water adding to give a fivefold dilution. <mdo:image height="112" width="411" src="D6.png" alt=""></mdo:image> e) To give a concentration of 125 cells/ml requires a dilution of 800 times. This can be easily decomposed into two tenfold dilutions and one eightfold dilution. Thus, the first two dilution steps involve taking 10ml of solution and adding 90ml of water, whereas the third step involve staking 10ml of solution and adding 70ml of water. The final step involves no addition of water. <mdo:image height="107" width="400" src="D7.png" alt=""></mdo:image> f) A concentration of 1875 cells/ml requires a dilution of $\frac{160}{3}$. We are essentially saying that $100000 \times \frac{3}{160} = 1875$, and so require up to four fractions which multiply together to give $\frac{3}{160}$. Three such fractions are $\frac{3}{5}$, $\frac{1}{8}$ and $\frac{1}{4}$. Thus, the first dilution involves taking 30ml of solution and adding 20ml of water; the second involves taking 10ml of solution and adding 70ml of water; the third involves taking 10ml of solution and adding 30ml of water; whereas the fourth requires no addition of water. <mdo:image height="113" width="406" src="D8.png" alt=""></mdo:image> 3) At each dilution stage it is possible to transfer between 10 and 100ml of solution (in 10ml intervals) and then add between 0 and 100ml (in 10ml intervals) of water. This gives a possibility of 110 different combinations, but unfortunately these are not all unique dilutions. For example, taking 10ml of solution and adding 10ml of water will give the same dilution as taking 20ml of solution and adding 20ml of water. By looking carefully at all these different dilutions (by writing them out!) it can be deduced that there are 64 different unique dilutions possible. 4) A dilution of 1/11 can be made very simple: just take 10ml of solution and add 100ml of water. However a dilution of 1/17 is impossible to make exactly: it cannot be created in a single dilution since no less than 10ml of solution can be taken, and no more than 100ml of water can be added. Also, because 17 is a prime number, it cannot be created in two or more dilutions. 5) A dilution of 1/21 can be made by recognising that the fraction can be written as a product of 1/3 and 1/7. Thus, using two dilutions 1/21 can be made: firstly take 10ml of solution and add 20ml of water. Next, take 10ml of this new solution and add 60ml of water. A dilution of 1/95 cannot be made exactly. 1/95 can be decomposed to 1/5 x 1/19. Although a dilution of 1/5 can be made, it is not possible to then dilution this by a factor of 19. This is because not only can a 1/19 dilution not be made in a single step, but also that it cannot be made in subsequent steps because 19 is a prime number. 6) Investigation of a few dilutions should hopefully indicate that dilutions cannot be made for reciprocals of prime numbers greater than 11 ! </mdoxml> <?xml version="1.0" encoding="UTF-8"?> <mdoxml version="1.0">It is not envisaged that <a href="http://nrich.maths.org/6164">this problem</a> would be used as a class problem. It is more appropriate for an enthusiastic student or small group of students looking for a challenge to work on independently.</mdoxml> <?xml version="1.0" encoding="UTF-8"?> <mdoxml version="1.0">Try working out what overall dilution factor is needed. Decompose this dilution factor into the product of up to four others. These will solve the problems... </mdoxml> <?xml version="1.0" encoding="UTF-8"?> <mdoxml version="1.0"> <mdo:image height="146" width="510" alt="" src="thirteenth.JPG"></mdo:image> I<a href="/content/id/6164/6164.swf">nteractivit</a>y <a href="/content/id/6164/6164.fla"></a> </mdoxml> 2 4 0 0 0 1 0 Investigating the dilution series Which dilutions can you make using only 10ml pipettes? Applications biology Applications chemistry Fractions, Decimals, Percentages, Ratio and Proportion Calculating with ratio & proportion Fractions, Decimals, Percentages, Ratio and Proportion Calculating with fractions Information and Communications Technology Interactivities Applications chemistry Admin Computer-based Applications STEM - living world Applications Maths Supporting SET Applications STEM - physical world