<?xml version="1.0" encoding="ISO-8859-1" ?>
  <resource>
  <id>548</id>
  <path>/www/nrich/html/content/98/01/six3/</path>
  <resourceTypeID>1</resourceTypeID>
  <last_published>2011-02-01T00:00:01</last_published>
  <indexXML>&lt;mdoxml version=&quot;1.0&quot;&gt;&lt;p&gt;The triangle ABC is isosceles with a right angle at B. In each diagram the triangle ABC has either a circle or one of two (different) squares inscribed within it.&lt;/p&gt;
&lt;p&gt;&lt;mdo:image alt=&quot;&quot; src=&quot;areas.jpg&quot;&gt;&lt;/mdo:image&gt;&lt;/p&gt;
&lt;p&gt;Which of the inscribed figures has the greatest area?&lt;/p&gt;
&lt;p&gt;&lt;a href=&quot;http://nrich.maths.org/7998&quot;&gt;Click here for a poster of this problem&lt;/a&gt;.&lt;/p&gt;
&lt;p&gt; &lt;/p&gt;&lt;/mdoxml&gt;</indexXML>
  <solutionXML>&lt;mdoxml version=&quot;1.0&quot;&gt;&lt;br&gt;&lt;/br&gt;

&lt;p class=&quot;editorial&quot;&gt;Many got the correct answer that the circle
which is embedded inside the isosceles triangle is the largest of
the three shapes.&lt;/p&gt;
&lt;p class=&quot;editorial&quot;&gt;Some students measured the diagrams given
which luckily had been drawn accurately to scale, while others
observed the symmetry of the isosceles triangle and the
consequences of joining B to D the mid point of AC. To find the
radius of the circle it helps to draw perpendiculars from the
centre to the sides of the triangle.&lt;/p&gt;
&lt;p class=&quot;editorial&quot;&gt;Taking the lengths of the short sides of the
triangle as $2$ units:&lt;/p&gt;
&lt;p class=&quot;editorial&quot;&gt;the radius of the circle is found to be
$2-\sqrt{2}$ and the area to be $\pi (6 - 4\sqrt{2})$.&lt;/p&gt;
&lt;p class=&quot;editorial&quot;&gt;the side length of square one to be $1$ and
area $1$;&lt;/p&gt;
&lt;p class=&quot;editorial&quot;&gt;and the side length of square two to be
$\frac{2\sqrt{2}}{3}$ and area $\frac{8}{9}$.&lt;/p&gt;
&lt;p&gt;&lt;span class=&quot;editorial&quot;&gt;Many students evaluated the ratio of the
areas as $1.078 : 1: 0.889$ (to $3$ dec. places)&lt;/span&gt;&lt;/p&gt;
&lt;p class=&quot;editorial&quot;&gt;&lt;span class=&quot;editorial&quot;&gt;Be&lt;/span&gt;n and
Adrianfrom the Simon Langton Grammar School for Boys used trig
ratios, as did Hannah of Maidstone Girls Grammar School, to arrive
at the same conclusions.&lt;/p&gt;
&lt;br&gt;&lt;/br&gt;&lt;/mdoxml&gt;</solutionXML>
  <noteXML>&lt;mdoxml version=&quot;1.0&quot;&gt;&lt;br&gt;&lt;/br&gt;
&lt;h3&gt;&lt;span style=&quot;font-weight: bold;&quot;&gt;Why do&lt;/span&gt; &lt;a href=&quot;http://nrich.maths.org/public/viewer.php?obj_id=548&quot; style=&quot;font-weight: bold;&quot;&gt;this problem&lt;/a&gt; &lt;span style=&quot;font-weight: bold;&quot;&gt;?&lt;/span&gt;&lt;/h3&gt;
This problem brings together ideas of areas of circles and squares,
the use of Pythagoras theorem and the property of tangents to a
circle from an exernal point.&lt;br&gt;&lt;/br&gt;
&lt;br&gt;&lt;/br&gt;
&lt;h3&gt;&lt;span style=&quot;font-weight: bold;&quot;&gt;Possible approach&lt;/span&gt;&lt;/h3&gt;
You might start with the middle diagram which is the easiest. It
brings in the ratio of the sides of an isosceles right angles
triangle which is again used in the other two parts.&lt;br&gt;&lt;/br&gt;
&lt;br&gt;&lt;/br&gt;
&lt;h3&gt;&lt;span style=&quot;font-weight: bold;&quot;&gt;Key questions&lt;/span&gt;&lt;/h3&gt;
If you know the side length of an isosceles right angled triange
how do you find the hypotenuse?&lt;br&gt;&lt;/br&gt;
&lt;br&gt;&lt;/br&gt;
Which lengths are equal in the digram?&lt;br&gt;&lt;/br&gt;
&lt;br&gt;&lt;/br&gt;
Which angles are equal?&lt;br&gt;&lt;/br&gt;
&lt;br&gt;&lt;/br&gt;
Can you use the symmetry of the diagram?&lt;br&gt;&lt;/br&gt;
&lt;br&gt;&lt;/br&gt;
&lt;h3&gt;&lt;span style=&quot;font-weight: bold;&quot;&gt;Possible extension&lt;/span&gt;&lt;/h3&gt;
The problem &lt;a href=&quot;http://nrich.maths.org/public/viewer.php?obj_id=2163&amp;amp;part=index&quot;&gt;
Circle-in&lt;/a&gt; also uses one of the circle theorems (the tangent is
perpendicular to the radius at the point of contact).&lt;br&gt;&lt;/br&gt;&lt;/mdoxml&gt;</noteXML>
  <clueXML>&lt;mdoxml version=&quot;1.0&quot;&gt;Draw in the radii of the circle. Use the symmetry in the
diagrams.&lt;br&gt;&lt;/br&gt;&lt;/mdoxml&gt;</clueXML>
  <canonXML/>
  <end_user_role>2</end_user_role>
  <difficulty>4</difficulty>
  <keystage1>0</keystage1>
  <keystage2>0</keystage2>
  <keystage3>0</keystage3>
  <keystage4>1</keystage4>
  <keystage4plus>0</keystage4plus>
  <title>Compare Areas</title>
  <description>Which has the greatest area, a circle or a square inscribed in an
isosceles, right angle triangle?</description>
  <spec_group>Measures and Mensuration
    <specifier>Area</specifier>
  </spec_group>
  <spec_group>2D Geometry, Shape and Space
    <specifier>Squares</specifier>
  </spec_group>
  <spec_group>2D Geometry, Shape and Space
    <specifier>Circle theorems</specifier>
  </spec_group>
  <spec_group>2D Geometry, Shape and Space
    <specifier>Pythagoras' theorem</specifier>
  </spec_group>
  <spec_group>2D Geometry, Shape and Space
    <specifier>Inscribed polygons</specifier>
  </spec_group>
  <spec_group>Information and Communications Technology
    <specifier>smartphone</specifier>
  </spec_group>
</resource>