<?xml version="1.0" encoding="UTF-8" ?>
  <resource>
  <id>2002</id>
  <path>/www/nrich/html/content/04/01/letme1/</path>
  <resourceTypeID>1</resourceTypeID>
  <last_published>2011-02-01T00:00:01</last_published>
  <indexXML>&lt;?xml version=&quot;1.0&quot; encoding=&quot;UTF-8&quot;?&gt;
&lt;mdoxml version=&quot;1.0&quot;&gt;&lt;br&gt;&lt;/br&gt;
&lt;p&gt;&lt;mdo:image align=&quot;left&quot; alt=&quot;Eggs in a basket&quot; height=&quot;140&quot; src=&quot;eggs_in_basket.gif&quot; width=&quot;124&quot;&gt;&lt;/mdo:image&gt; There are three baskets, a brown one, a red one and a pink one, holding a total of ten eggs.&lt;/p&gt;
&lt;p&gt;The Brown basket has one more egg in it than the Red basket.&lt;/p&gt;
&lt;p&gt;The Red basket has three eggs less than the Pink basket.&lt;/p&gt;
&lt;p&gt;How many eggs are in each basket?&lt;/p&gt;
&lt;div&gt; &lt;/div&gt;
&lt;div&gt;&lt;a href=&quot;http://nrich.maths.org/7200&amp;amp;part=&quot;&gt;Click here for a poster of this problem&lt;/a&gt;.  &lt;/div&gt;
&lt;br&gt;&lt;/br&gt;&lt;/mdoxml&gt;</indexXML>
  <solutionXML>&lt;?xml version=&quot;1.0&quot; encoding=&quot;UTF-8&quot;?&gt;
&lt;mdoxml version=&quot;1.0&quot;&gt;&lt;p class=&quot;editorial&quot;&gt;We had over two hundred solutions to this
problem! I'm just sorry that we can't mention you all.&lt;/p&gt;
&lt;p class=&quot;editorial&quot;&gt;There seemed to be two different ways that you
used to solve it. Some of you tried out numbers in a logical way
until you found the ones that worked, like Erika from East Bergholt
High School who wrote:&lt;/p&gt;
&lt;blockquote&gt;
&lt;p&gt;If there was 1 egg in the brown basket, no eggs in the red
basket and 3 eggs in the pink basket, that would only make 4
eggs.&lt;br&gt;&lt;/br&gt;
If there were 2 eggs in the brown basket, 1 egg in the red basket
and 4 eggs in the pink basket, this only makes 7 eggs.&lt;br&gt;&lt;/br&gt;
So finally, if there were 3 eggs in the brown basket, 2 eggs in the
red basket and 5 eggs in the pink basket, there would be 10 eggs
altogether.&lt;/p&gt;
&lt;/blockquote&gt;
&lt;p class=&quot;editorial&quot;&gt;Absolutely correct - thank you Erika.&lt;/p&gt;
&lt;p class=&quot;editorial&quot;&gt;Phoebe, Alice and Luke from Cambridge also did
the problem in this kind of way, but they used counters to help
them. Their Dad explained how they went about finding the
solution:&lt;/p&gt;
&lt;blockquote&gt;
&lt;p&gt;Each had a piece of A4 paper and a pencil which was coloured
either red, brown or pink. They drew a basket on their paper in the
colour they had been given. They had 10 counters between them to
represent the eggs. Phoebe read out the conditions and they started
with 4 counters in the red basket, 4 in the brown and 2 in the
pink. However, they knew this didn't satisfy the first condition
(that the brown basket had to have one more egg than the red) so
Alice moved one counter from the red basket to the brown basket.
But they soon realised that now there were 5 in the brown and only
3 in the red, so still the first condition wasn't satisfied. The
three of them talked about it more and took one counter out of the
brown basket, so now there were 4 in the brown and 3 in each of the
red and the pink. However, this didn't satisfy the second condition
(that the red has three less than the pink). After playing around
with the counters a bit more, they eventually found the solution -
the red basket has 2 eggs, the brown basket has 3 eggs and the pink
has 5.&lt;/p&gt;
&lt;/blockquote&gt;
&lt;p class=&quot;editorial&quot;&gt;Well done! It can be a very good idea to use
some sort of &amp;quot;equipment&amp;quot; to help answer problems.&lt;/p&gt;
&lt;p class=&quot;editorial&quot;&gt;Jas from Greenpark Combined School solved the
problem algebraically:&lt;/p&gt;
&lt;p&gt;Red basket = n eggs&lt;br&gt;&lt;/br&gt;
Brown basket = n+1 eggs&lt;br&gt;&lt;/br&gt;
Pink basket = n+3 eggs&lt;br&gt;&lt;/br&gt;
Total eggs = 10, so&lt;br&gt;&lt;/br&gt;
n + (n+1) + (n+3) = 10&lt;br&gt;&lt;/br&gt;
3n + 4 = 10&lt;br&gt;&lt;/br&gt;
3n = 6&lt;br&gt;&lt;/br&gt;
n = 2&lt;br&gt;&lt;/br&gt;
So, brown basket - 3eggs&lt;br&gt;&lt;/br&gt;
red basket - 2 eggs&lt;br&gt;&lt;/br&gt;
pink basket - 5 eggs&lt;/p&gt;
&lt;p class=&quot;editorial&quot;&gt;Also, a very clear solution. Well done.&lt;/p&gt;
&lt;br&gt;&lt;/br&gt;&lt;/mdoxml&gt;</solutionXML>
  <noteXML>&lt;?xml version=&quot;1.0&quot; encoding=&quot;UTF-8&quot;?&gt;
&lt;mdoxml version=&quot;1.0&quot;&gt;&lt;div class=&quot;embed&quot;&gt;
&lt;h2&gt;Eggs in Baskets&lt;/h2&gt;
&lt;br&gt;&lt;/br&gt;
&lt;p&gt;&lt;mdo:image align=&quot;left&quot; alt=&quot;Eggs in a basket&quot; height=&quot;140&quot; src=&quot;eggs_in_basket.gif&quot; width=&quot;124&quot;&gt;&lt;/mdo:image&gt; There are three baskets, a brown one, a red one and a pink one, holding a total of ten eggs.&lt;/p&gt;
&lt;p&gt;The Brown basket has one more egg in it than the Red basket.&lt;/p&gt;
&lt;p&gt;The Red basket has three eggs less than the Pink basket.&lt;/p&gt;
&lt;p&gt;How many eggs are in each basket?&lt;/p&gt;
&lt;div&gt; &lt;/div&gt;
&lt;div&gt;&lt;a href=&quot;http://nrich.maths.org/7200&amp;amp;part=&quot;&gt;Click here for a poster of this problem&lt;/a&gt;.  &lt;/div&gt;
&lt;/div&gt;
&lt;br&gt;&lt;/br&gt;
&lt;h3&gt;&lt;span style=&quot;font-weight: bold;&quot;&gt;Why do this problem?&lt;/span&gt;&lt;/h3&gt;
&lt;div&gt;&lt;a href=&quot;http://nrich.maths.org/public/viewer.php?obj_id=2002&amp;amp;part=index&quot;&gt;This problem&lt;/a&gt; involves addition and subtraction, and requires children to work on three interdependent conditions simultaneously - the number of eggs must be ten, the brown basket has one more than the red basket and the pink basket three more than the red. Realising that changing the eggs in one basket affects
the others takes a sophisticated bit of reasoning. The problem could be used to focus on children&amp;#39;s mathematical representations and it is a good context in which to talk about using trial and improvement, combined with a systematic approach.&lt;/div&gt;
&lt;br&gt;&lt;/br&gt;
&lt;h3&gt;Possible approach&lt;/h3&gt;
&lt;div&gt;Mark Dawes from Comberton Village College created &lt;a href=&quot;/content/04/01/letme1/Eggs_in_Baskets.notebook&quot;&gt;this Smart notebook file&lt;/a&gt; and &lt;a href=&quot;/content/04/01/letme1/Eggs-in-baskets-differentiation-sheets.ppt&quot;&gt;these sheets in PowerPoint&lt;/a&gt; which you may find useful if you follow this suggested approach.&lt;/div&gt;
&lt;br&gt;&lt;/br&gt;
&lt;div&gt;You could start off with pictures of three bags on the board and suggest that there are six sweets in total inside the bags. Using the spotlight tool on the interactive whiteboard (or simply by drawing in spots to represent sweets), reveal that the first bag contains two sweets and the second three. Invite pupils to say how many sweets the third bag contains and to explain how they know. You
could then ask children to draw or write on their mini-whiteboards to show another way of putting six sweets into three bags. Some may draw pictures, others may write number sentences, for example. Share these different representations among the whole group and talk about the advantages of each.&lt;/div&gt;
&lt;br&gt;&lt;/br&gt;
&lt;div&gt;You could then set up a new situation with three boxes drawn on the board and, for example, three apples in the first box. Tell the children that the second box has two more apples than the first box (you could have this written on the board to reveal) and discuss what that tells us about the number in the second box. Then say that the third box has two apples less than the first box and
talk about this in a similar way. Ask learners to work together to find other numbers of apples that could go in each box. When you share their suggestions, draw attention to those children who used trial and improvement combined with some sort of system, for example by trying four apples in the first box, then five etc. They may also have tried smaller numbers of apples in the first box and it
would be interesting to encouarge them to explain what happened.&lt;/div&gt;
&lt;br&gt;&lt;/br&gt;
&lt;div&gt;You can then introduce the children to the problem as it stands - it might help to reveal the information a bit at a time. Give pairs plenty of time to work on it on mini-whiteboards or large sheets of A3 paper, using any representation they feel is helpful. You may also find having counters or some other objects to represent the eggs would be useful.&lt;/div&gt;
&lt;br&gt;&lt;/br&gt;
&lt;div&gt;The plenary can be used to share different ways of working on the problem as well as the solution itself. You can discuss the advantages and disadvantages of each method, which will help children select appropriate methods on subsequent occasions.&lt;/div&gt;
&lt;br&gt;&lt;/br&gt;
&lt;h3&gt;Key questions&lt;/h3&gt;
&lt;div&gt;What have you tried so far?&lt;/div&gt;
&lt;div&gt;Why don&amp;#39;t you choose a number of eggs for the pink basket? How many would be in the red basket, then? And how many in the brown basket?&lt;/div&gt;
&lt;div&gt;How many eggs is this in total?&lt;/div&gt;
&lt;div&gt;What could you try instead?&lt;/div&gt;
&lt;div&gt;How will you know that you haven&amp;#39;t missed out the combination that works?&lt;/div&gt;
&lt;br&gt;&lt;/br&gt;
&lt;br&gt;&lt;/br&gt;
&lt;h3&gt;Possible extension&lt;/h3&gt;
&lt;div&gt;Once the children have solved this first question, give them the opportunity to make up one of their own. A writing frame such as this could be useful:&lt;/div&gt;
&lt;br&gt;&lt;/br&gt;
&lt;div style=&quot;margin-left: 40px;&quot;&gt;There are 3 baskets, a (colour).one, a (colour) one and a (colour) one, holding a total of (number of) eggs.&lt;/div&gt;
&lt;div style=&quot;margin-left: 40px;&quot;&gt; &lt;/div&gt;
&lt;div style=&quot;margin-left: 40px;&quot;&gt;The (colour) basket has (number) more egg in it than the (colour) basket.&lt;/div&gt;
&lt;div style=&quot;margin-left: 40px;&quot;&gt; &lt;/div&gt;
&lt;div style=&quot;margin-left: 40px;&quot;&gt;The (colour) basket has (number) eggs less than the (colour) basket.&lt;/div&gt;
&lt;div style=&quot;margin-left: 40px;&quot;&gt; &lt;/div&gt;
&lt;div style=&quot;margin-left: 40px;&quot;&gt;How many eggs are in each basket?&lt;/div&gt;
&lt;br&gt;&lt;/br&gt;
&lt;div&gt;Most will realise after a short time that the easiest way is to start with eggs in the baskets, (i.e. the answer)and concoct the question from that. They could then offer it to a friend to see if they can work it out.&lt;/div&gt;
&lt;br&gt;&lt;/br&gt;
&lt;h3&gt;Possible support&lt;/h3&gt;
&lt;div&gt;Using sheets printed from &lt;a href=&quot;/content/04/01/letme1/Eggs-in-baskets-differentiation-sheets.ppt&quot;&gt;this PowerPoint file&lt;/a&gt; will help children structure their work. In addition, providing &lt;a href=&quot;/content/04/01/letme1/EggsInBaskets.doc&quot;&gt;vocabulary cards&lt;/a&gt; so that the children can make word sentences to describe the number of eggs they have put into each basket will be useful.
Alternatively, you could offer questions about just two baskets.&lt;/div&gt;
&lt;br&gt;&lt;/br&gt;
&lt;br&gt;&lt;/br&gt;&lt;/mdoxml&gt;</noteXML>
  <clueXML>&lt;?xml version=&quot;1.0&quot; encoding=&quot;UTF-8&quot;?&gt;
&lt;mdoxml version=&quot;1.0&quot;&gt;&lt;br&gt;&lt;/br&gt;
&lt;p&gt;You could start by imagining that the brown basket has one egg
in it. How many would be in the red and pink
baskets?&lt;/p&gt;
&lt;p&gt;Try other numbers of eggs in the brown basket.&lt;/p&gt;
&lt;p&gt;You might find it helpful to draw pictures or jot some things
down on paper.&lt;/p&gt;
&lt;br&gt;&lt;/br&gt;&lt;/mdoxml&gt;</clueXML>
  <canonXML>&lt;?xml version=&quot;1.0&quot; encoding=&quot;UTF-8&quot;?&gt;
&lt;mdoxml version=&quot;1.0&quot;&gt;&lt;br&gt;&lt;/br&gt;

&lt;p class=&quot;editorial&quot;&gt;We had over two hundred solutions to this
problem! I'm just sorry that we can't mention you
all.&lt;/p&gt;
&lt;p class=&quot;editorial&quot;&gt;There seemed to be two different ways that you
used to solve it. Some of you tried out numbers in a logical way
until you found the ones that worked, like Erika from East Bergholt
High School who wrote:&lt;/p&gt;
&lt;blockquote&gt;
&lt;p&gt;If there was 1 egg in the brown basket, no eggs in the red
basket and 3 eggs in the pink basket, that would only make 4
eggs.&lt;br&gt;&lt;/br&gt;
If there were 2 eggs in the brown basket, 1 egg in the red basket
and 4 eggs in the pink basket, this only makes 7 eggs.&lt;br&gt;&lt;/br&gt;
So finally, if there were 3 eggs in the brown basket, 2 eggs in the
red basket and 5 eggs in the pink basket, there would be 10 eggs
altogether.&lt;/p&gt;
&lt;/blockquote&gt;
&lt;p class=&quot;editorial&quot;&gt;Absolutely correct - thank you Erika.&lt;/p&gt;
&lt;p class=&quot;editorial&quot;&gt;Phoebe, Alice and Luke from Cambridge also did
the problem in this kind of way, but they used counters to help
them. Their Dad explained how they went about finding the
solution:&lt;/p&gt;
&lt;blockquote&gt;
&lt;p&gt;Each had a piece of A4 paper and a pencil which was coloured
either red, brown or pink. They drew a basket on their paper in the
colour they had been given. They had 10 counters between them to
represent the eggs. Phoebe read out the conditions and they started
with 4 counters in the red basket, 4 in the brown and 2 in the
pink. However, they knew this didn't satisfy the first condition
(that the brown basket had to have one more egg than the red) so
Alice moved one counter from the red basket to the brown basket.
But they soon realised that now there were 5 in the brown and only
3 in the red, so still the first condition wasn't satisfied. The
three of them talked about it more and took one counter out of the
brown basket, so now there were 4 in the brown and 3 in each of the
red and the pink. However, this didn't satisfy the second condition
(that the red has three less than the pink). After playing around
with the counters a bit more, they eventually found the solution -
the red basket has 2 eggs, the brown basket has 3 eggs and the pink
has 5.&lt;/p&gt;
&lt;/blockquote&gt;
&lt;p class=&quot;editorial&quot;&gt;Well done! It can be a very good idea to use
some sort of &amp;quot;equipment&amp;quot; to help answer problems.&lt;/p&gt;
&lt;p class=&quot;editorial&quot;&gt;Jas from Greenpark Combined School solved the
problem algebraically:&lt;/p&gt;
&lt;p&gt;Red basket = n eggs&lt;br&gt;&lt;/br&gt;
Brown basket = n+1 eggs&lt;br&gt;&lt;/br&gt;
Pink basket = n+3 eggs&lt;br&gt;&lt;/br&gt;
Total eggs = 10, so&lt;br&gt;&lt;/br&gt;
n + (n+1) + (n+3) = 10&lt;br&gt;&lt;/br&gt;
3n + 4 = 10&lt;br&gt;&lt;/br&gt;
3n = 6&lt;br&gt;&lt;/br&gt;
n = 2&lt;br&gt;&lt;/br&gt;
So, brown basket - 3eggs&lt;br&gt;&lt;/br&gt;
red basket - 2 eggs&lt;br&gt;&lt;/br&gt;
pink basket - 5 eggs&lt;/p&gt;
&lt;p class=&quot;editorial&quot;&gt;Also, a very clear solution. Well done.&lt;/p&gt;
&lt;br&gt;&lt;/br&gt;&lt;/mdoxml&gt;</canonXML>
  <end_user_role>2</end_user_role>
  <difficulty>4</difficulty>
  <keystage1>1</keystage1>
  <keystage2>0</keystage2>
  <keystage3>0</keystage3>
  <keystage4>0</keystage4>
  <keystage4plus>0</keystage4plus>
  <title>Eggs in Baskets</title>
  <description>There are three baskets, a brown one, a red one and a pink one, holding a total of 10 eggs. Can you use the information given to find out how many eggs are in each basket?</description>
  <spec_group>Using, Applying and Reasoning about Mathematics
    <specifier>Trial and improvement</specifier>
  </spec_group>
  <spec_group>Calculations and Numerical Methods
    <specifier>Addition &amp; subtraction</specifier>
  </spec_group>
  <spec_group>Admin
    <specifier>Lower primary mapping document</specifier>
  </spec_group>
</resource>