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  <last_published>2011-02-01T00:00:01</last_published>
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You have four jugs of 9, 7, 4 and 2 litres capacity. The 9 litre
jug is full of wine, the others are empty.&lt;br&gt;&lt;/br&gt;
Can you divide the wine into three equal quantities? &lt;br&gt;&lt;/br&gt;
Can you do it in different ways?&lt;br&gt;&lt;/br&gt;
&lt;br&gt;&lt;/br&gt;
You have three jugs one of which is full and holds 8 litres. The
capacity of other jugs is not known. But, it is known that when
using them every whole number quantity from 1 litre to 8 litres can
be accurately measured out. &lt;br&gt;&lt;/br&gt;
What could be the capacities of the 2 other jugs? &lt;br&gt;&lt;/br&gt;
How would you measure all the whole number quantities from 1 to 8
litres?&lt;br&gt;&lt;/br&gt;
&lt;br&gt;&lt;/br&gt;
&lt;mdo:image height=&quot;310&quot; width=&quot;589&quot; alt=&quot;&quot; src=&quot;2d.gif&quot;&gt;&lt;/mdo:image&gt;&lt;br&gt;&lt;/br&gt;
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&lt;mdoxml version=&quot;1.0&quot;&gt;&lt;p class=&quot;editorial&quot;&gt;This is a very well-explained solution submitted by Julia (Wymondham High School):&lt;/p&gt;
&lt;br&gt;&lt;/br&gt;
&lt;div&gt;For the jugs holding 9, 7, 4, and 2 litres, this flow diagram shows how the solution can be achieved in three distinct ways, using eight decantings of the wine. In each case, the 9 litres of wine are being poured back and forth to achieve the required result. We order the jugs by size and use a four digit number to represent the volume of wine in each jug. For example 9000 means there are 9
litres in the 9 litre jug, and the 7, 4 and 2 litre jugs are empty. The solution is found when we have 3330, where 3 litres are in each of the 9, 7 and 4 litre jugs; and the 2 litre jug is empty.&lt;/div&gt;
&lt;mdo:image alt=&quot;&quot; height=&quot;602&quot; src=&quot;flow.gif&quot; width=&quot;419&quot;&gt;&lt;/mdo:image&gt;&lt;br&gt;&lt;/br&gt;
&lt;br&gt;&lt;/br&gt;
To measure out all the integer amounts from 1 to 8 litres using three jugs, one of which is full and holds 8 litres, there are several possible solutions. For example, for jugs with capacities 8, 3 and 2 litres, the following triples give the numbers of litres in each of the jugs at successive steps and all the amounts from 1 litre to 8 litres occur at some stage of the process: (8,0,0) (5,3,0)
(5,1,2) (7,1,0) (7,0,1) (6,0,2) (6,2,0) (4,2,2). There are other solutions for capacities of 8, 4 and 3; for 8, 5 and 4; for 8, 5 and 1 etc.
&lt;p class=&quot;editorial&quot;&gt; &lt;/p&gt;
&lt;p class=&quot;editorial&quot;&gt;Two other different students from Wymondham High School, David and Rachel, also submitted good solutions. In their answers, they included a very useful table of results which showed at a glance the state of the jugs after any particular pouring.&lt;/p&gt;
&lt;br&gt;&lt;/br&gt;
&lt;p class=&quot;editorial&quot;&gt;Much later two students from Flegg High, Luke and Ian, also submitted a successful solution to this problem. They had found their answer after &quot;hours of trouble, and help from Mrs Fenn&quot;.&lt;/p&gt;
&lt;br&gt;&lt;/br&gt;
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  <title>Jugs of Wine</title>
  <description>You have four jugs of 9, 7, 4 and 2 litres capacity. The 9 litre
jug is full of wine, the others are empty. Can you divide the wine
into three equal quantities?</description>
  <spec_group>Calculations and Numerical Methods
    <specifier>Addition &amp; subtraction</specifier>
  </spec_group>
  <spec_group>Secondary Mapping Document
    <specifier>Number operations and calculation methods</specifier>
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