<?xml version="1.0" encoding="UTF-8" ?>
  <resource>
  <id>1823</id>
  <path>/www/nrich/html/content/03/07/15plus4/</path>
  <resourceTypeID>1</resourceTypeID>
  <last_published>2011-02-01T00:00:01</last_published>
  <indexXML>&lt;?xml version=&quot;1.0&quot; encoding=&quot;UTF-8&quot;?&gt;
&lt;mdoxml version=&quot;1.0&quot;&gt;&lt;br&gt;&lt;/br&gt;
Use the diagram to prove the double angle formula, where $t=\tan
\theta$: $$\tan2\theta = {2t\over {1-t^2}},\quad \sin2\theta =
{2t\over {1+t^2}},\quad \cos2\theta = {{1-t^2}\over {1+t^2}}$$&lt;br&gt;&lt;/br&gt;
&lt;mdo:image alt=&quot;Tan&quot; src=&quot;tan.gif&quot;&gt;&lt;/mdo:image&gt;&lt;br&gt;&lt;/br&gt;
&lt;br&gt;&lt;/br&gt;
The point $P'=(p',q')$ is the image of the point $P=(p,q)$ after
reflection in the line $y=mx$. To find $(p',q')$ use the fact that
the midpoint of $PP'$ is on the line $y=mx$ and the line segment
$PP'$ is perpendicular to the line $y=mx$ and show that
$$p'=p\cos2\theta + q\sin2\theta,\ q'=p\sin2\theta -
q\cos2\theta\quad (1)$$ where $m=\tan\theta$. Hence establish
another proof that the matrix&lt;br&gt;&lt;/br&gt;
&lt;br&gt;&lt;/br&gt;
$$T_2= \left( \begin{array}{cc} \cos 2\theta &amp;amp;\sin2\theta \\
\sin2\theta &amp;amp;-\cos2\theta \end{array} \right) $$&lt;br&gt;&lt;/br&gt;
&lt;br&gt;&lt;/br&gt;
gives a reflection in the line $y=x\tan\theta$. The point
$P''=(p'',q'')$ is the image of the point $P'$ after reflection in
the line $y=x\tan\phi$. Apply the transformation $$T_2' = \left(
\eqalign{\cos 2\phi &amp;amp;\sin2\phi \\ \sin2\phi &amp;amp;
-\cos2\phi}\right)$$ to the point $P'=(p',q')$ to find the
coordinates of the point $P''$ in terms of $p, q, \theta$ and
$\phi$. Hence show that the combination of two reflections in
distinct intersecting lines is a rotation about the point of
intersection by twice the angle between the two mirror lines. What
is the effect of the two reflections if the lines coincide (i.e.
$\theta=\phi$)?&lt;br&gt;&lt;/br&gt;&lt;/mdoxml&gt;</indexXML>
  <solutionXML>&lt;?xml version=&quot;1.0&quot; encoding=&quot;UTF-8&quot;?&gt;
&lt;mdoxml version=&quot;1.0&quot;&gt;&lt;br&gt;&lt;/br&gt;
Andrei Lazanu proved the double angle formulae illustrated in the
diagram: &lt;br&gt;&lt;/br&gt;
&lt;br&gt;&lt;/br&gt;
The diagram starts from a right angled triangle, of sides $2t$ and
2 and where consequently $\tan\theta = t$. In this triangle, a line
making an angle $\theta$ with the hypotenuse is drawn. This way, an
isosceles triangle is formed, and $2\theta$ is the angle exterior
to this isosceles triangle. Let the sides DA and DB of this
isosceles triangle be $x$\ units. Then the length of DC must be
$2-x$ units. Using Pythagoras' Theorem for triangle ADC we find
$x$. $$x^2=(2t)^2+(2-x)^2.$$ Hence $x=1+t^2$ and so the length of
side DC is $2-(1+t^2)=1-t^2$. &lt;br&gt;&lt;/br&gt;
&lt;br&gt;&lt;/br&gt;
The formulae for the sine, cosine and tangent of $2\theta$ in terms
of $t$, where $t=\tan \theta$, follow directly from the ratios of
the sides of the right angled triangle ADC and we get $$\tan2\theta
= {2t\over {1-t^2}},\quad \sin2\theta = {2t\over {1+t^2}},\quad
\cos2\theta = {{1-t^2}\over {1+t^2}}$$ &lt;br&gt;&lt;/br&gt;

&lt;div&gt;&lt;a href=&quot;http://nrich.maths.org/public/viewer.php?obj_id=1822&amp;amp;part=solution&quot; class=&quot;editorial&quot;&gt;Rots and Refs&lt;/a&gt; &lt;span class=&quot;editorial&quot;&gt;provides a proof of the translation formula&lt;/span&gt;
   .&lt;/div&gt;
&lt;br&gt;&lt;/br&gt;

&lt;div&gt;Finally, to find the combined transformation you have to
multiply the transformation matricies to get (using the double
angle formulae to simplify):&lt;/div&gt;
&lt;br&gt;&lt;/br&gt;
$$T= \left( \begin{array}{cc} cos 2(\phi-\theta) &amp;amp;
-sin2(\phi-\theta)\\ sin2(\phi-\theta &amp;amp; \cos2(\phi-\theta)
\end{array} \right) $$ &lt;br&gt;&lt;/br&gt;
 
&lt;div&gt;Which is a rotation. If the angles are equal the matrix would
be:&lt;/div&gt;
&lt;br&gt;&lt;/br&gt;
&lt;div&gt;$$T= \left( \begin{array}{cc} 1 &amp;amp; 0\\ 0 &amp;amp; 1
\end{array} \right) $$&lt;/div&gt;
So the two reflections combined would leave all points unchanged.
&lt;br&gt;&lt;/br&gt;
&lt;br&gt;&lt;/br&gt;&lt;/mdoxml&gt;</solutionXML>
  <noteXML/>
  <clueXML>&lt;?xml version=&quot;1.0&quot; encoding=&quot;UTF-8&quot;?&gt;
&lt;mdoxml version=&quot;1.0&quot;&gt;&lt;br&gt;&lt;/br&gt;
The conditions suggested in the question give you two equations
which you can solve to find $p'$ and $q'$. Use the same formulation
to give $(p'',q'')$. &lt;br&gt;&lt;/br&gt;
&lt;br&gt;&lt;/br&gt;
The problem &lt;a href=&quot;http://nrich.maths.org/public/viewer.php?obj_id=1821&amp;amp;part=index&quot;&gt;
'The Matrix'&lt;/a&gt; explains how 2 by 2 matrices are used to give
transformations of the plane and how you multiply the position
vector of a point by the matrix to find the image of that point
under the transformation. &lt;br&gt;&lt;/br&gt;&lt;/mdoxml&gt;</clueXML>
  <canonXML>&lt;?xml version=&quot;1.0&quot; encoding=&quot;UTF-8&quot;?&gt;
&lt;mdoxml version=&quot;1.0&quot;&gt;&lt;/mdoxml&gt;</canonXML>
  <end_user_role>2</end_user_role>
  <difficulty>5</difficulty>
  <keystage1>0</keystage1>
  <keystage2>0</keystage2>
  <keystage3>0</keystage3>
  <keystage4>0</keystage4>
  <keystage4plus>1</keystage4plus>
  <title>Reflect Again</title>
  <description>Follow hints to investigate the matrix which gives a reflection of the plane in the line y=tanx. Show that the combination of two reflections in intersecting lines is a rotation.</description>
  <spec_group>Coordinates and Coordinate Geometry
    <specifier>Cartesian equations of lines</specifier>
  </spec_group>
  <spec_group>Trigonometry
    <specifier>Trigonometric identities</specifier>
  </spec_group>
  <spec_group>Transformations and their Properties
    <specifier>Reflections</specifier>
  </spec_group>
  <spec_group>Transformations and their Properties
    <specifier>Compound transformations</specifier>
  </spec_group>
  <spec_group>Transformations and their Properties
    <specifier>Matrix transformations</specifier>
  </spec_group>
</resource>