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Cyclic quadrilaterals are quadrilaterals with all four of their vertices on a circle.&lt;br&gt;&lt;/br&gt;
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You can have cyclic polygons of any number of sides.&lt;br&gt;&lt;/br&gt;
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Not all quadrilaterals are cyclic. Perhaps you can draw a quadrilateral that is not cyclic - how do you know it is not cyclic?&lt;br&gt;&lt;/br&gt;
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All triangles are cyclic - how could you prove this?&lt;br&gt;&lt;/br&gt;
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Cyclic quadrilaterals have some interesting features and in this brief article we invite you to look at some of them and we suggest ideas for looking further:&lt;br&gt;&lt;/br&gt;
&lt;p&gt;&lt;mdo:image alt=&quot;&quot; border=&quot;0&quot; src=&quot;a1.gif&quot;&gt;&lt;/mdo:image&gt;&lt;/p&gt;
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Consider any cyclic quadrilateral $P Q R S$ with vertices on a circle centre $C$.&lt;br&gt;&lt;/br&gt;
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Draw chord $Q S$ and radii $P C$, $Q C$ and $S C$.&lt;br&gt;&lt;/br&gt;
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Let angle $Q P C=x$ degrees and angle $S P C=y$ degrees.&lt;br&gt;&lt;/br&gt;
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This means that angle $Q P S=(x+y)$ degrees.&lt;br&gt;&lt;/br&gt;
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The angles of the isosceles triangle $P Q C$ are $x$ degrees, $x$ degrees and $(180-2x)$ degrees.&lt;br&gt;&lt;/br&gt;
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The angles of the isosceles triangle $P S C$ are $y$ degrees, $y$ degrees and $(180-2y)$ degrees.&lt;br&gt;&lt;/br&gt;
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Angle $Q C S=360$ degrees $-$ angle $Q C P -$ angle $S C P=(2x+2y)$ degrees.&lt;br&gt;&lt;/br&gt;
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This shows that angle $Q C S$ is twice angle $Q P S$.&lt;br&gt;&lt;/br&gt;
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We say that angle $Q P S$ is subtended by the arc $Q R S$ and this basic property leads to the following theorems.
&lt;p&gt;You might like to use the &lt;a href=&quot;http://nrich.maths.org/public/viewer.php?obj_id=2883&amp;amp;part=2883&quot;&gt;Geoboard environment&lt;/a&gt; and some of the problems that were published in &lt;a href=&quot;http://nrich.maths.org/public/monthindex.php?year=2005&amp;amp;month=07&amp;amp;choice=3&amp;amp;showfulltier=yes&amp;amp;submit=GO&quot;&gt;July 2005&lt;/a&gt; to help investigate these ideas practically before moving into the theory.&lt;/p&gt;
&lt;p&gt;&lt;strong&gt;&lt;u&gt;Theorem 1.&lt;/u&gt;&lt;/strong&gt;&lt;/p&gt;
&lt;p&gt;The angle at the centre of a circle is twice the angle at the circumference subtended by the same arc.&lt;/p&gt;
&lt;p&gt;Because angle $Q C S$ is the same for all positions of $P$, Theorem 1 shows angle $Q P S$ is the same regardless of where $P$ lies.&lt;/p&gt;
&lt;p&gt;&lt;a href=&quot;http://nrich.maths.org/public/viewer.php?obj_id=2845&amp;amp;part=2845&quot;&gt;See this problem&lt;/a&gt; for a practical demonstration of this theorem.&lt;/p&gt;
&lt;p&gt;&lt;u&gt;&lt;strong&gt;Theorem 2.&lt;/strong&gt;&lt;/u&gt;&lt;/p&gt;
&lt;p&gt;All angles in the same segment of a circle are equal (that is angles at the circumference subtended by the same arc).&lt;/p&gt;
&lt;p&gt;&lt;strong&gt;&lt;u&gt;Theorem 3.&lt;/u&gt;&lt;/strong&gt;&lt;/p&gt;
&lt;p&gt;The angle subtended by a semicircle (that is the angle standing on a diameter) is a right angle. See &lt;a href=&quot;http://nrich.maths.org/public/viewer.php?obj_id=2847&amp;amp;part=2847&quot;&gt;this problem&lt;/a&gt; for a practical demonstration of this theorem.&lt;/p&gt;
&lt;p style=&quot;font-weight: bold; text-decoration: underline;&quot;&gt;Theorem 4.&lt;/p&gt;
&lt;p&gt;Opposite angles of a cyclic quadrilateral add up to 180 degrees. See &lt;a href=&quot;http://nrich.maths.org/public/viewer.php?obj_id=2865&amp;amp;part=2865&quot;&gt;this problem&lt;/a&gt; for a practical demonstration of this theorem.&lt;/p&gt;
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  <end_user_role>2</end_user_role>
  <difficulty>3</difficulty>
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  <title>The Cyclic Quadrilateral</title>
  <description>
This gives a short summary of the properties and theorems of cyclic quadrilaterals and links to some practical examples to be found elsewhere on the site.

</description>
  <spec_group>2D Geometry, Shape and Space
    <specifier>Circle theorems</specifier>
  </spec_group>
  <spec_group>2D Geometry, Shape and Space
    <specifier>Cyclic</specifier>
  </spec_group>
  <spec_group>2D Geometry, Shape and Space
    <specifier>Quadrilaterals</specifier>
  </spec_group>
</resource>