Let the large circles have radius R.

${\displaystyle \mathrm{Area}A=2x\pi x(\frac{1}{2}R){}^2=1/2\pi R^2}$

${\displaystyle \mathrm{Area}B=3x\frac{1}{2}x{R}^{2}x\frac{\sqrt{3}}{2}=\frac{3}{4}\sqrt{3}{R}^2}$

${\displaystyle \mathrm{Area}C=(2R^2)-\pi R^2=(4-\pi )R^2}$

${\displaystyle \mathrm{Area}D=2x\frac{1}{2}x{R}^2=R^2}$

${\displaystyle \mathrm{Area}E=\pi R^2(\sqrt{2}R){}^2=(\pi -2)R^2}$