We received a solution from Andisheh from Spring Field School. His reasoning was correct but he used the wrong figures, so we are using his response as a basis for the solution:

hexagon in circle

Imagine extending the radius so that you have a horizontal diameter.

The hexagon is now split into two identical trapeziums (trapezia?).

Area of one trapezium

=  1

2
height x sum of parallel sides

=  1

2
 × Ö0.75 × (2 + 1)

=  3

4
x Ö3

The area of the hexagon is therefore:  3

2
 × Ö3

The area of the triangle is half the area of the hexagon.

triangle drawn in hexagon by joining alternate vertices


The area of the triangle is therefore  3

4
 × Ö3