We had over 100 solutions for this challenge.
From Heage school we had solutions from Miles, Eleanor, Ellie, Erin, Olivia, Brogan, Ruby and Phoebe.
From Riverside International School of Prague in the Czech Republic we had solutions from Sabrina, George, Tereza, Ieuan, Catalina, Jewoo, Daniel and Michelle.
From Thameside primary School we had solutions from Devon, Jade, Rebekah, Harry, Jordan, Chelsea.
From St. Helen's C of E School solutions came from Jay, Neve, Lily, Alice, Saba, Sam, Jamie, Thomas, Will, Ollie, Aaron, Oliver, Jack, Katie, Tilly, Holly, Matthew, Caitlin, Esme, Oliver and Courtney.
From Brewers Hill School Paige, Brandon, Paul, Daniel, Shannon, Leigha, Kai, Maia-storme, Max, John, Lucy and Jacob sent in solutions.
From Shebbear Community School we had solutions from Rebecca, Maddie, Megs, Samual, Lewis, Grace, Emma, Ellie, Paige, Megan, Jade, Kelsy and Keeley.
From Clatford C of E Primary School Finn, Hugo, Sydney, Alice, Tabby sent in solutions.
From Paddox Primary School we had solutions from Arjan, Lucy, Stephanie, Claire, Charlie, Jess and Mia. 
Lewis from Oatlands School sent in a very interesting solution in a Word format unfortunately it was too pale to satisfactorily transfer for us.
Other solutions came in from Ruth & Martha, Rober, Daniel, Maddison, Bethany, Alex, Oliver, Claire, Mlee, George, Gokhan, Shay Adesh, Seval, Erica, Barney, Jahelm, Ayaan, Jack, Rosa, Wilf, Finn, Ralph & Niamh, Miss Blake's Mathematical Team of clever girls, Kieran, Thomas, Miyazur, Olti, Year 6, Anna, Isaac, Emma, Ted, Thomas, Izzy from the UK, Iris from New Zealand, Julius from SIS Maennedorf in Switzerland, Henry from USA .

Year 6 pupils from St John Fisher Harrogate Magic maths Club

We started off by thinking of all the possible ways of making the totals. This took a long time.
We thought that it would be best to make the biggest totals first, using the bigger numbers to make them.
14 = 9+5, 13 = 6 + 7, 1 + 2 = 3, 4+3 = 7 and 8 + 0 = 8.
Some of us did it the other way round, making the smallest totals first, with the smallest numbers.
1 + 2 = 3, 4 + 3 = 7, 8 + 0 = 8, 7 + 6 = 13 and 9 + 5 = 14.
We could also come with pairs randomly but its quicker to use a strategy.
7 + 0 = 7, 5 + 3 = 8, 9 + 4 = 13, 6 + 8 = 14 and 1 + 2 = 3.

Ieuan from Riverside School, Prague in the Czech Republic wrote;

At first I was randomly picking numbers, and on my first attempt doing it I found a  , 0+7=7 5+3=8 9+4 =13 6+8=14 2+1=3. And then I tried using a system from then on off adding a number to the smaller number then subtracting one from the smaller number, but it did not go very well because when I converted 5+3 to 4+4 I realised that you cannot do that.
Then I found out something quite clever that from one onward each 2 numbers have the same amount of possibilities, for example 2 and 3 have 2 possibilities, 4 and 5 have have 3, 6 and 7 have 4, 8 and 9 have 5 and it goes on forever! So I wrote down all the possibilities for 7,8,13,14,3.
Then I shortened it so if i use 13 as an example,13+0, 12+1, 10+3, 9+4, 8+5, 7+6. Then I would take off 13+0, 12+1 and 10+3 and do that for all the rest! So when I had all the possibilities I did 2 attempts without succeding then I got one and I started explaining it on here, but I realised I had found the same   as my first attempt. Then I did one attempt and I found another   3+0, 8+6, 9+4, 7+1 and 2+5.

Well this has received the largest number of solutions I have had to read. A big well done to you all and I'm sorry I could not show everyone's thinking that they did to get a solution.