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It is known that given any three non intersecting
circles in the plane there is another circle or
straight line that cuts the three given circles at
right angles. (The circle or straight line is said to
be orthogonal to the 3 original circles.)
Given three circles with centres $(0, 0)$, $(3, 0)$ and
$(9, 2)$ and radii $5$, $4$ and $6$ respectively find
the centre and radius of the circle that cuts the three
given circles at right angles. Draw the circles to
check that the circle you have found appears to be
orthogonal to the others.
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What happens in the case of three circles with centres at $(0, 0)$, $(3, 3)$ and $(8, 8)$ and radii $1$, $2$ and $3$ respectively?
Given three circles, how can you tell without calculating which of the two cases applies, an orthogonal circle or an orthogonal straight line?