Here you need to start with
a(n) = 1+2+3+...+n = 1 2 n(n+1) b(n) = 12 + 22 + 32 +...+ n2 = 1 6 n(n+1)(2n+1) c(n) = 13 + 23 + 33 +...+ n3 = 1 4 n2 (n+1 )2 .

These are well known results found in many text books and you will find proofs in some problems on this website. See Picture Story and Natural Sum.